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chetverikova78
@chetverikova78
July 2022
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Решить уравнение 3^(х+3)+3^х= 5*2^(х+4)-17*2^х
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Moriska2018
3 ^ (x+3)+3 ^x =5*2^(x+4) -17*2^x
(3 ^ x)*3^3+3 ^x =5*(2^x)*(2^4) -17*2^x
27*(3 ^ x)+3 ^x =5*(2^x)*16 -17*2^x
28*(3 ^ x) =80*(2^x) -17*2^x
28*(3 ^ x) =63*(2^x)
(3/2)^x=63/28
x=log по основанию (3/2) от (63/28)
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chetverikova78
Это окончательный ответ
Moriska2018
Да
chetverikova78
Почему 28*(3^х)?
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Answers & Comments
(3 ^ x)*3^3+3 ^x =5*(2^x)*(2^4) -17*2^x
27*(3 ^ x)+3 ^x =5*(2^x)*16 -17*2^x
28*(3 ^ x) =80*(2^x) -17*2^x
28*(3 ^ x) =63*(2^x)
(3/2)^x=63/28
x=log по основанию (3/2) от (63/28)