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Reevinko
@Reevinko
August 2022
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Решить уравнение: 3x(в квадрате)+5x=2
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anmih
Verified answer
3х²+5х=2
3х²+5х-2=0
Д=25+4*3*2=25+24=49
х(1)=(-5+7)/6=2/6=
1/3
х(2)=(-5-7)/6 = -12/6=
-2
1 votes
Thanks 0
tanigur
дискриминант не правильный получился
anmih
Обнови стр
tanigur
3x²+5x=2
3x²+5x-2=0
D=b²-4ac=5²-4*3*(-2)=25+24=49
D=49
D>0=>2 корня
х1= -b+√D / 2a=-5+7/6=2/6=1/3
x2=-b-√D/2a=-5-7/6=-12/6=-2
Ответ: x1=1/3;x2=-2
2 votes
Thanks 1
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Answers & Comments
Verified answer
3х²+5х=23х²+5х-2=0
Д=25+4*3*2=25+24=49
х(1)=(-5+7)/6=2/6=1/3
х(2)=(-5-7)/6 = -12/6=-2
3x²+5x-2=0
D=b²-4ac=5²-4*3*(-2)=25+24=49
D=49
D>0=>2 корня
х1= -b+√D / 2a=-5+7/6=2/6=1/3
x2=-b-√D/2a=-5-7/6=-12/6=-2
Ответ: x1=1/3;x2=-2