Kixcertborn2

Verified answer

4(3y+1)²-27=(4y+9)(4y-9)+2(5y+2)(2y-7)

4(9y^2+6y+1)-27=16y^2-81+(10y+4)*(2y-7)

36y^2+24y+4-27=16y^2-81+20y^2-70y+8y-28

36y^2+24y-23=36y^2-109-62y

24y-23=-109-62y

24y+62y=-109+23

86y=-86

y=-1

lena25073 4(3y+1)²-27=(4y+9)(4y-9)+2(5y+2)(2y-7)
4(9у²+6у+1)-27=16у²-81+2(10у²-35у+4у-14)
36у²+24у+4-27-16у²+81-20у²+70у-8у+28=0
86у+86=0
86у=-86
у=-86/86
у=-1