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nikas9
@nikas9
July 2022
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Решить уравнение: 4sin^2 x +2cos^2 x -3sin2x=0
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murkins
Делим все на cos^2x:
4tg^2x+2-6sinxcosx/cos^2x=0
4tg^2x+2-6tgx=0
y=tgx
4y^2-6y+2=0
2y^2-3y+1=0
D=9-8=1
x1=(3+1)/4=1
x2=2/4=1/2
tgx=1
x=pi/4+pi*n
tgx=1/2
x=arctg(1/2)+pi*n
Ответ: x1=pi/4+pi*n, x2=arctg(1/2)+pi*n
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AnonimusPro
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Решение на фото внизу
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Answers & Comments
4tg^2x+2-6sinxcosx/cos^2x=0
4tg^2x+2-6tgx=0
y=tgx
4y^2-6y+2=0
2y^2-3y+1=0
D=9-8=1
x1=(3+1)/4=1
x2=2/4=1/2
tgx=1
x=pi/4+pi*n
tgx=1/2
x=arctg(1/2)+pi*n
Ответ: x1=pi/4+pi*n, x2=arctg(1/2)+pi*n
Verified answer
Решение на фото внизу