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jdmiloveyou
@jdmiloveyou
July 2022
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Решить уравнение 4sinx*cosx*cos2x*cos8x=sin12x.
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let5
2sin2x*cos2x*cos8x=sin12x
sin4x*cos8x=sin12x
1/2(sin12x+sin4x)=sin12x
1/2sin12x+1/2sin4x-sin12x=0
1/2sin4x-1/2sin12x=0
1/2*2sin(-4x)*cos8x=0
-sin4x*cos8x=0
sin4x*cos8x=0
sin4x=0 или cos8x=0
4x=
, n-целое
x=
, n-целое
cos8x=0
8x=
, n - целое
x=
, n - целое
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jdmiloveyou
Как вы получили третью строчку?
let5
Формула преобразование произведения тригонометрических функций в сумму sina*cosb=1/2(sin(a+b)+sin(a-b))
let5
1/2(sin12x+sin(-4x)=sin12x
1/2sin12x-1/2sin4x-sin12x=0
-1/2sin4x-1/2sin12x=0
let5
sin4x+sin12x=0
let5
sin8x*cos4x=0
let5
sin8x=0 или cos4x=0
let5
x=pi n/8 x=pi/8+pi n/4
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Answers & Comments
sin4x*cos8x=sin12x
1/2(sin12x+sin4x)=sin12x
1/2sin12x+1/2sin4x-sin12x=0
1/2sin4x-1/2sin12x=0
1/2*2sin(-4x)*cos8x=0
-sin4x*cos8x=0
sin4x*cos8x=0
sin4x=0 или cos8x=0
4x=, n-целое
x=, n-целое
cos8x=0
8x=, n - целое
x=, n - целое
1/2sin12x-1/2sin4x-sin12x=0
-1/2sin4x-1/2sin12x=0