Home
О нас
Products
Services
Регистрация
Войти
Поиск
Wasted23
@Wasted23
June 2022
1
30
Report
решить уравнение
5sin^2 x+6cosx-6=0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Graver9062
5sin²x +6cosx-6=0
5-5cos²x+6cosx-6=0
5cos²-6cosx+1=0
Пусть cos x =t; |t|≤0
5t²-6t+1=0
D=36-20=16
√D=4
t=1
t=0,4
cos x=1
x=π+2πk
cos x =0,4
x= ± arccos0,4+2πk
Ответ: {π+2πk; ±arccos0,4+2πk | k€Z}
6 votes
Thanks 9
More Questions From This User
See All
Wasted23
November 2021 | 0 Ответы
3...
Answer
Wasted23
November 2021 | 0 Ответы
najdite resheniya uravneniya cos2xsin2x koren iz 3cosx0 prinadlezhashie otrezku
Answer
Wasted23
June 2021 | 0 Ответы
najti oblast opredeleniya funkcii u log po osnovaniyu pi chisla 105h 10 5xg
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "решить уравнение 5sin^2 x+6cosx-6=0..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
5-5cos²x+6cosx-6=0
5cos²-6cosx+1=0
Пусть cos x =t; |t|≤0
5t²-6t+1=0
D=36-20=16
√D=4
t=1
t=0,4
cos x=1
x=π+2πk
cos x =0,4
x= ± arccos0,4+2πk
Ответ: {π+2πk; ±arccos0,4+2πk | k€Z}