Решить уравнение -(6x-1)^2+(4x+3)(4x-3)+18=0. Created by lambert1337. matematika-ru

Решить уравнение -(6x-1)^2+(4x+3)(4x-3)+18=0...

August 2022 2 5 Report

Решить уравнение
-(6x-1)^2+(4x+3)(4x-3)+18=0

INGL500 -(6x-1)^2+(4x+3)(4x-3)+18=0
(4x-3)(4x+3)-(6x-1)^2+18=0
-20x^2+12x+8=0
Решаем через Дискриминант:
a=-20;b=12;c=8
D=12^2-4*(-20)*8=784
x1=-2/5
x2=1
Ответ:-2/5 и 1

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nedenispolybomy $-(6x-1)^2+(4x+3)(4x-3)+18=0; \\
-(6x^2-6x+1)+(16x^2-9)+18=0; \\
-36x^2+12x-1+16x^2-12x+12x-9+18=0; \\
-20x^2+12x+8=0; \\
-4(x-1)(5x+2)=0; \\
x-1=0; \ x_1=1; \\
5x+2=0; \ x_2=-0,4$

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