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evaanisimova
@evaanisimova
July 2022
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Решить уравнение: А)15-(6-x)²=x(2-x)=? Б)(5x+2)²-25(x-3)(x+3)=29=?
В)64y²-49=0 .
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Edward2121
1)15-(6-x)² = x(2 - x)15-36 + 12x - x² = 2x - x²12x - 2x = 2110x = 21
x = 2,1
( 5x + 2 )² -25(x-3 )(x +3 ) = 2925x² + 20x + 4 - 25( x² - 9 ) = 2925x²+ 20x + 4 - 25x² + 225 = 2920x = 29 - 229x = - 200/20x =-10
64y² - 49 = 0( 8y - 7 )( 8y + 7 ) = 0 a²-b²=(a+b)(a-b)8y - 7 = 0 y (1)= 7/88y + 7 = 0 y (2)= - 7/8
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Answers & Comments
x = 2,1
( 5x + 2 )² -25(x-3 )(x +3 ) = 2925x² + 20x + 4 - 25( x² - 9 ) = 2925x²+ 20x + 4 - 25x² + 225 = 2920x = 29 - 229x = - 200/20x =-10
64y² - 49 = 0( 8y - 7 )( 8y + 7 ) = 0 a²-b²=(a+b)(a-b)8y - 7 = 0 y (1)= 7/88y + 7 = 0 y (2)= - 7/8