Решить уравнение: cos^2(pi-x)+8cos(pi+x)+7=0. Created by lirooy08. matematika-ru

Решить уравнение: cos^2(pi-x)+8cos(pi+x)+7=0...

August 2022 1 25 Report

Решить уравнение: cos^2(pi-x)+8cos(pi+x)+7=0

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rudlarpar Cos^2(pi-x)+8cos(pi+x)+7=0 cos^2 x-8cosx+7=0 cosx=t t^2 -8t+7=0 D=64-28=36 t=(8+6)/2=7 t=(8-6)/2=1 cosx=7(нет решений, т.к. cos не может быть больше 1) cosx=1 x=2pin

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lirooy08 October 2021 | 0 Ответы

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