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nastyaromanova14
@nastyaromanova14
July 2022
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Решить уравнение: х(х+5)=(х+3)²
х(х(х-1))+6=х(х+3)(х-4)
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brodonatik
х(х+5)=(х+3)²=
=x^2+5x=x^2+6x+9
=5x=6x+9
=5x-6x=9
-x=9|:(-1)
=-9
х(х(х-1))+6=х(х+3)(х-4)
=x*(x^2-x)+6=(x^2+3x)*(x-4)=
=x^3-x^2+6=x^3-4x^2+3x^2-12x=
=-x^2+6=-4x^2+3x^2-12x=
=-x^2+6=-x^2-12=
6=-12x
-12x=6|:(-12)
x=-6/12 x=-1/2 или -0,5
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Answers & Comments
=x^2+5x=x^2+6x+9
=5x=6x+9
=5x-6x=9
-x=9|:(-1)
=-9
х(х(х-1))+6=х(х+3)(х-4)
=x*(x^2-x)+6=(x^2+3x)*(x-4)=
=x^3-x^2+6=x^3-4x^2+3x^2-12x=
=-x^2+6=-4x^2+3x^2-12x=
=-x^2+6=-x^2-12=
6=-12x
-12x=6|:(-12)
x=-6/12 x=-1/2 или -0,5