Решить уравнение ....пожалуйста. Created by anutabelze. matematika-ru

Решить уравнение ....пожалуйста...

CVita $\frac{1}{x}+ \frac{1}{x-1}= \frac{2}{x+1} \\ (x-1)(x+1)+x(x+1)=2x(x-1) \\ x^2-1+x^2+x=2x^2-2x \\ 2x^2-2x^2+x+2x=1 \\ 3x=1 \\ x= \frac{1}{3}$

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Светланаskrip $\frac{1}{x}+ \frac{1}{x-1}= \frac{2}{x+1} \\ \frac{1}{x}+ \frac{1}{x-1}-\frac{2}{x+1}=0 \\ \\ \frac{(x-1)(x+1)+x(x+1)-2x(x-1)}{x(x+1)(x-1)}=0 \\ \\ \frac{x^{2}-1+x^{2}+x-2x^{2}+2x}{x(x+1)(x-1)}=0 \\ \\ x^{2}-1+x^{2}+x-2x^{2}+2x=0 \\ \\ 3x=1 \\ \\ x= \frac{1}{3}$

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