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HERGUS
@HERGUS
July 2022
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Решить уравнение:
sin3x + √3 * cos3x = 2
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sedinalana
2(1/2*
sin3x + √3/2 * cos3x) = 2
sin(3x+
π/3)=1
3x+π/3=π/2+2πk
3x=-π/3+π/2+2πk
3x=π/6+2πk
x=π/18+2πk/3,k∈z
1 votes
Thanks 1
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Answers & Comments
sin(3x+π/3)=1
3x+π/3=π/2+2πk
3x=-π/3+π/2+2πk
3x=π/6+2πk
x=π/18+2πk/3,k∈z