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Felceana
@Felceana
July 2022
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Решить уравнение: (x-3)^2+(3-x)(x+3)=(x+2)^2-x^2
(^2-степень)
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verhoturceva88
(x-3)^2+(3-x)(x+3)=(x+2)^2-x^2
(x-3)^2+(3-x)(x+3)=x^2+4x+4-x^2
(x-3)^2+9-x^2=x^2+4x+4-x^2
x^2-6x+9+9=x^2+4x+4
-6x+9+9=4x+4
-6x-4x=4-18
-10x=-14
x=1.4
2 votes
Thanks 1
21vanya12
(x-3)^2+(3-x)(x+3)=(x+2)^2-x^2
x^2-6x+9+3x+9-x^2-3x=x^2+4x+4-x^2
-6x-4x-4+18=0
-10x=-14
x=1.4
1 votes
Thanks 1
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Answers & Comments
(x-3)^2+(3-x)(x+3)=x^2+4x+4-x^2
(x-3)^2+9-x^2=x^2+4x+4-x^2
x^2-6x+9+9=x^2+4x+4
-6x+9+9=4x+4
-6x-4x=4-18
-10x=-14
x=1.4
x^2-6x+9+3x+9-x^2-3x=x^2+4x+4-x^2
-6x-4x-4+18=0
-10x=-14
x=1.4