Решить уравнение: (X-3)^2+(x+4)^2-(x-5)^2=17x+24. Created by nikitintima46. algebra-ru

Решить уравнение: (X-3)^2+(x+4)^2-(x-5)^2=17x+24...

July 2022 2 8 Report

Решить уравнение:
(X-3)^2+(x+4)^2-(x-5)^2=17x+24

Artem112

Verified answer

$(x-3)^2+(x+4)^2-(x-5)^2=17x+24
\\\
x^2-6x+9+x^2+8x+16-x^2+10x-25-17x-24=0
\\\
x^2-5x-24=0
\\\
D=25+4\cdot24=121
\\\
x_1= \frac{5+11}{2}=8
\\\
 x_1= \frac{5-11}{2}=-3$
Ответ: 8 и -3

19 votes Thanks 56

кляча

Verified answer

X^2 -6x+9+x^2+8x+16 -x^2+10x-25-17x-24 =0
x^2 -5x -24 =0
D = 25 -4(-24) =Y121; D=11
x1= (5+11)/2 =8
x2 =(5-11)/2 = -3

6 votes Thanks 25

Tima7373 ^2 -6x+9+x^2+8x+16 -x^2+10x-25-17x-24 =0
x^2 -5x -24 =0
D = 25 -4(-24) =Y121; D=11
x1= (5+11)/2 =8
x2 =(5-11)/2 = -3

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