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OVI1320
@OVI1320
August 2022
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РЕШИТЬ УРАВНЕНИЕ
√(x-√(x-2))+√(x+√(x-2))=3
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schnega12
X2-3x+√3-x=√3-x+10
x2-3x+√3-x-√3+x-10=0
x2-3x-10=0
D=(-3)^2-4×1×(-10)=9+40=49
x1=3+7/2×1=10/2=5
x2=3-7/2×1=-4/2=-2
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Answers & Comments
x2-3x+√3-x-√3+x-10=0
x2-3x-10=0
D=(-3)^2-4×1×(-10)=9+40=49
x1=3+7/2×1=10/2=5
x2=3-7/2×1=-4/2=-2