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ruksana
@ruksana
August 2022
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Решить уравнение: x^2 +4x +2^√(x+2) +3=0
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AndreW0000
Ответ: x = -2
(-2)^2 + 4 * (-2) + 2^0 + 3 = 4 -8 +1 +3 = 0
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Answers & Comments
(-2)^2 + 4 * (-2) + 2^0 + 3 = 4 -8 +1 +3 = 0