Решить уравнение x^3-3x^2+6x-4=0
х³ - 3х² + 6х - 4 = 0
х³ - х² - 2х² + 2х + 4х - 4 = 0
х²•(х - 1) - 2х•(х - 1) + 4•(х - 1) = 0
(х - 1)•(х² - 2х + 4) = 0
Ответ: 1
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х³ - 3х² + 6х - 4 = 0
х³ - х² - 2х² + 2х + 4х - 4 = 0
х²•(х - 1) - 2х•(х - 1) + 4•(х - 1) = 0
(х - 1)•(х² - 2х + 4) = 0
Ответ: 1