Home
О нас
Products
Services
Регистрация
Войти
Поиск
лоза10
@лоза10
July 2022
2
5
Report
решить уравнение
(х-2)(х²+2х+1)=4(х+1)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
lymovroma
(х-2)(х²+2х+1) = 4(х+1)
(х-2)(х+1)² - 4(х+1)=0
(х+1)((х-2)(х+1) - 4) = 0
х+1 = 0 (х-2)(х+1) - 4 = 0
х1 = -1 х² - х - 6 = 0
по т. Виетта
х2 = - 2, х3 = 3
0 votes
Thanks 2
crdd
(х-2)(х²+2х+1)=4(х+1)
(х-2)(х+1)²-4(х+1)=0
(х+1)((х-2)(х+1)-4)=0
(х+1)(х²-2х-2+х-4) =0
(х+1)(х²-х-6)=0
х+1=0
х=-1
или
х²-х-6=0
D=1+24=25
x=(1-5):2=-2
x=(1+5):2=3
ответ: -2;-1;3
1 votes
Thanks 2
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "решить уравнение(х-2)(х²+2х+1)=4(х+1)..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(х-2)(х+1)² - 4(х+1)=0
(х+1)((х-2)(х+1) - 4) = 0
х+1 = 0 (х-2)(х+1) - 4 = 0
х1 = -1 х² - х - 6 = 0
по т. Виетта
х2 = - 2, х3 = 3
(х-2)(х+1)²-4(х+1)=0
(х+1)((х-2)(х+1)-4)=0
(х+1)(х²-2х-2+х-4) =0
(х+1)(х²-х-6)=0
х+1=0
х=-1
или
х²-х-6=0
D=1+24=25
x=(1-5):2=-2
x=(1+5):2=3
ответ: -2;-1;3