Решить уравнения
1) x^2 - 4x + 4 =0
2) x^2 - 6x + 9 =0
3) (5-2x)^2 - 1 = x(4x + 2)
4) (2x - 3)^2 + 2 = 4x(x - 1)
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Решить уравнения
1) x^2 - 4x + 4 =0
2) x^2 - 6x + 9 =0
3) (5-2x)^2 - 1 = x(4x + 2)
4) (2x - 3)^2 + 2 = 4x(x - 1)
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Answers & Comments
1) (x-2)^2 => x = 2
Или же за теоремой Виета: x1=2 x2=2
2)За теоремой Виэта:
X1=3 x2=3
3)25-20x+4x^2-1=4x^2+2x
22x=24
x = 24/22 = 1 и 2/22
4)4x^2-12x+9+2=4x^2-4x
-8x=-11
x=11/8= 1 и 3/8 = 1,375