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chechina2000
@chechina2000
July 2022
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решить уравнения 25y^4-y^2=0 и 4x^4-x^2=0
хелп ми, плизз
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maleevvladislav
25у^4-y²=0
y²(25y²-1)=0
у²=0 или 25у²-1=0
у=0 (5у-1)(5у+1)=0
5у=1 5у=-1
у=0,2 у=-0,2
-4х^4-х²=0
-х²(4х²+1)
-х²=0 4х²+1=0
х=0 4х²=-1
х²=-0,25
х=корней нет
4 votes
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Answers & Comments
y²(25y²-1)=0
у²=0 или 25у²-1=0
у=0 (5у-1)(5у+1)=0
5у=1 5у=-1
у=0,2 у=-0,2
-4х^4-х²=0
-х²(4х²+1)
-х²=0 4х²+1=0
х=0 4х²=-1
х²=-0,25
х=корней нет