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olga200873
@olga200873
July 2022
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Решить уравнения: (3x+4)2-16=0,где 2 степень, 2x в кубе+4x в квадрате=8(x+2)
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ilred
(3x+4)^2-16=0
36x^2+6x+16-16=0
36x^2+6x=0
6x(6x+1)=0
6x=0 6x+1=0
x=0 x=-1/6
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Answers & Comments
36x^2+6x+16-16=0
36x^2+6x=0
6x(6x+1)=0
6x=0 6x+1=0
x=0 x=-1/6