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vladakukoyashnaya
@vladakukoyashnaya
July 2022
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Решить уравнения :
а) sin 2x + 2 cos x = 0
б) cos 4x + sin2^2x = 0
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Answers & Comments
Sonya336
А) 2sin(x)cos(x)+2cos(x)=0
cos(x)=0 sin(x)=-1
x=
x=
б) cos²x-sin²x+sin²x=cos²x=0
(1+cos2x)/2=0
1+cos2x=0
cos2x=-1
2x=
x=
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Answers & Comments
cos(x)=0 sin(x)=-1
x=
x=
б) cos²x-sin²x+sin²x=cos²x=0
(1+cos2x)/2=0
1+cos2x=0
cos2x=-1
2x=
x=