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vladakukoyashnaya
@vladakukoyashnaya
July 2022
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Решить уравнения :
а ) sin 2x + 2 cos x = 0
б) cos 4x + sin22x = 0
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avilov41
Sin2x+2cosx=0
2sinxcosx+2cosx=0
2cosx(sinx+1)=0,
cosx=0, x=π/2+πn,n∈z,
sinx+1=0 , sinx=-1, x=-π/2+2πn,n∈z
2) cos4x+sin^22x=0,
cos^22x-sin^22x+sin^22x=0,
cos^22x =0, 2x=π/2+πn,n∈z, x=π/4+πn/2,n∈z..
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Answers & Comments
2sinxcosx+2cosx=0
2cosx(sinx+1)=0,
cosx=0, x=π/2+πn,n∈z,
sinx+1=0 , sinx=-1, x=-π/2+2πn,n∈z
2) cos4x+sin^22x=0,
cos^22x-sin^22x+sin^22x=0,
cos^22x =0, 2x=π/2+πn,n∈z, x=π/4+πn/2,n∈z..