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Anyta01op
@Anyta01op
August 2022
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Решить уравнинения и неравенства
3(5х+2)>х-(3х-23)
4(х+8)-7(х-1)=12
3х^2-27=0
5х^2-4=0
Х^2-1<0
Пожалуйста, с подробным решением!) Заранее спасибо♥
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Dимасuk
Verified answer
3(5x + 2) > x - (3x - 23)
15x + 6 > x - 3x + 23
15x + 6 > -2x + 23
15x + 2x > 23 - 6
17x > 17
x > 1
.
4(x + 8) - 7(x - 1) = 12
4x + 32 - 7x + 7 = 12
-3x = 12 - 32 - 7
-3x = -27
x = 9
.
3x² - 27 = 0
3(x² - 9) = 0
(x - 3)(x + 3) = 0
x = -3; 3.
5x² - 4 = 0
(x√5 - 2)(x√5 + 2) = 0
x = -2/√5; 2/√5
.
x² - 1 < 0
(x - 1)(x + 1) < 0
+ -1|||||||||-||||||||||||1 +
------------0-------------------0-----------> x
x ∈ (-1; 1).
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Answers & Comments
Verified answer
3(5x + 2) > x - (3x - 23)15x + 6 > x - 3x + 23
15x + 6 > -2x + 23
15x + 2x > 23 - 6
17x > 17
x > 1.
4(x + 8) - 7(x - 1) = 12
4x + 32 - 7x + 7 = 12
-3x = 12 - 32 - 7
-3x = -27
x = 9.
3x² - 27 = 0
3(x² - 9) = 0
(x - 3)(x + 3) = 0
x = -3; 3.
5x² - 4 = 0
(x√5 - 2)(x√5 + 2) = 0
x = -2/√5; 2/√5.
x² - 1 < 0
(x - 1)(x + 1) < 0
+ -1|||||||||-||||||||||||1 +
------------0-------------------0-----------> x
x ∈ (-1; 1).