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DianaG13
@DianaG13
July 2022
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Решить вариант В2. Позязя =)
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sedinalana
Verified answer
A
(x+2)(x-1)≠0⇒x≠-2,x≠1
(4x-1)(x-1)=(2x+12)(x+2)
4x²-4x-x+1-2x²-4x-12x-24=0
2x²-21x-23=0
D=441+184=625
x1=(21-25)/4=-1
x2=(21+25)/4=10,75
б
(x-2)(x+2)≠0⇒x≠2;x≠-2
(x-1)(x-2)+x(x+2)=8
x²-2x-x+2+x²+2x-8=0
2x²-x-6=0
D=1+48=49
x1=(1-7)/4=-1,5
x2=(1+7)/4=2 не удов усл
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Verified answer
A(x+2)(x-1)≠0⇒x≠-2,x≠1
(4x-1)(x-1)=(2x+12)(x+2)
4x²-4x-x+1-2x²-4x-12x-24=0
2x²-21x-23=0
D=441+184=625
x1=(21-25)/4=-1
x2=(21+25)/4=10,75
б
(x-2)(x+2)≠0⇒x≠2;x≠-2
(x-1)(x-2)+x(x+2)=8
x²-2x-x+2+x²+2x-8=0
2x²-x-6=0
D=1+48=49
x1=(1-7)/4=-1,5
x2=(1+7)/4=2 не удов усл