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katyaposelkina
@katyaposelkina
August 2022
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Решить ( x^2+3x)^2-2(x^2+3x)-8=0
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massg
Обозначим x^2+3x = y
y^2-2y-8=0 y1= -2 y2=4
x^2+3x+2=0 x1= -2 x2= -1
x^2+3x-4=0 x3= -4 x4 = 1
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Answers & Comments
y^2-2y-8=0 y1= -2 y2=4
x^2+3x+2=0 x1= -2 x2= -1
x^2+3x-4=0 x3= -4 x4 = 1