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diamas750
@diamas750
August 2021
2
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решить задание №2 срочно!!!!!!!!!
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sedinalana
Verified answer
(4x²-1)/(x+1)²-3x²/(x+1)²=(4x²-1-3x²)/(x+1)²=(x²-1)/(x+1)²=
=(x-1)(x+1)/9x+1)²=(x-1)/(x+1)
x=1/3
(1/3-1):(1/3+1)=-2/3:4/3=-2/3*3/4=-1/2
2 votes
Thanks 1
diamas750
/ идет как разделить?
diamas750
или дробная черта?
katnakobzeva2
4x в квадрате-1-3х в квадрате/x в квадрате+2х+1=х в квадрате-1/x в квадрате+2х+1
при х=1/3 то x в квадрате-1/x в квадрате+2х+1=1/9-1///1/9+2/3+1=9/9-1/9///1/9+6/9+1=8/9///9/16=1/2=0.5
1 votes
Thanks 1
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Answers & Comments
Verified answer
(4x²-1)/(x+1)²-3x²/(x+1)²=(4x²-1-3x²)/(x+1)²=(x²-1)/(x+1)²==(x-1)(x+1)/9x+1)²=(x-1)/(x+1)
x=1/3
(1/3-1):(1/3+1)=-2/3:4/3=-2/3*3/4=-1/2
при х=1/3 то x в квадрате-1/x в квадрате+2х+1=1/9-1///1/9+2/3+1=9/9-1/9///1/9+6/9+1=8/9///9/16=1/2=0.5