Решить задания которые сверху,буду благодарен если будут обьяснения. Created by ssssss1979. algebra-ru

12(√a-√b)(√a+√b)/√(ab)(√a+√b)=(√a-√b)/√(ab)3a)8x³=1x³=1/8x=1/2b){3x-2≥0⇒3x≥2⇒x≥2/3{4-x≥0⇒x≤4x∈[2/3;4]3x-2=((4-x)²3x-2=16-8x+x²x²-11x+18=0x1+x2=11 U x1*x2=18x1=2x2=9 не удов усл4(√x-√y)9√x+√y)=8√x-√y=2√x+√y=8:2=4прибавим 2 последних2√x=6√x=3x=9√y=4-3=1y=1Ответ (9;1)Новые вопросы в АлгебраДАЮ 30 балів!!!!система рівняння графічнах-2у=1у-х=-2Алгебра ДПА 9 класс 2 вариант 1.7Алгебра Мерзляк ДПА 9 класс 1.9 1 вариантАлгебра Мерзляк ДПА 9 классДопоможітьбудь ласка Знайдіть суму 100 перших членів послідовності аn, якщо ат = 2n+1Варіанти відповідей1020020400120001020a1=-5; d=6. Скільки треба взяти членів прогресії, щоб їх сума дорівнювала 35?Варіанти відповідей25730Помогите пожайлуста даю 70 балов!!!Верно ли,что если сумма a² + b²(a и b натуральные)делятся на 11,то числа a и b делятся на 11?Срочно с решениемПЛИСПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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Решить задания которые сверху,буду благодарен если будут обьяснения...

ssssss1979 @ssssss1979

July 2022 1 1 Report

Решить задания которые сверху,буду благодарен если будут обьяснения

Answers & Comments

sedinalana 1
$\sqrt[4]{(7- \sqrt{33} )(7+ \sqrt{33} ) } = \sqrt[4]{49-33} = \sqrt[4]{16} =2$
2
(√a-√b)(√a+√b)/√(ab)(√a+√b)=(√a-√b)/√(ab)
3
a)8x³=1
x³=1/8
x=1/2
b){3x-2≥0⇒3x≥2⇒x≥2/3
{4-x≥0⇒x≤4
x∈[2/3;4]
3x-2=((4-x)²
3x-2=16-8x+x²
x²-11x+18=0
x1+x2=11 U x1*x2=18
x1=2
x2=9 не удов усл
4
(√x-√y)9√x+√y)=8
√x-√y=2
√x+√y=8:2=4
прибавим 2 последних
2√x=6
√x=3
x=9
√y=4-3=1
y=1
Ответ (9;1)