Решить..........................................................&hearts;. Created by DHAcity. algebra-ru

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izabella9 $1)\quad y=-\frac{2}{x}\\\\y(4)=-\frac{2}{4}=-\frac{1}{2}=-0,5\\\\y(- \frac{1}{4} )=- \frac{2}{-1/4} =8\\\\y(\frac{2}{3})=-\frac{2}{2/3}=-3\\\\y(\frac{4}{7})=-\frac{2}{4/7}=-\frac{7}{2}=-3,5\\\\y(-12)=-\frac{2}{-12}=\frac{1}{6}\\\\y(\frac{1}{2})=-\frac{2}{1/2}=-4\\\\y(16)=-\frac{2}{16}=-\frac{1}{8}=-0,125\\\\y(-\frac{2}{9})=-\frac{2}{-2/9}=9$

$2)\quad A(4;2)\quad \to \quad x_0=4\; ,\; \; y_0=2\\\\y=\frac{16}{x}\; ;\; \; \frac{16}{4}=4\ne 2\; \; \to \; \; \; A\notin y(x)\\\\y= \frac{1}{4x} \; ;\; \; \frac{1}{4\cdot 4}=\frac{1}{16}\ne 2\; \; \to \; \; \; A\notin y(x)\\\\y= \frac{8}{x}\; ;\; \; \; \frac{8}{4} =2=y_0\quad \to \; \; \; A\in y(x)\\\\y=- \frac{8}{x}\; ;\; \; \; - \frac{8}{4} =-2\ne 2\; \; \; \to \; \; A\notin y(x)$

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DHAcity в номере 1 ГДЕ (е)и (ж) ??

izabella9 ж)y=-2/16=-1/8

izabella9 з)y=-2/(-2/9)=9

izabella9 просто не увидела*

NNNLLL54

Verified answer

#1
а)y=-2/4=-1,5
б)y=-2/(-1/4)=8
в)y=-2/(2/3)=-3
г)y=-2/(4/7)=-3,5
д)y=-2/(-12)=1/6
е) y=-2/(1/2)= -4
.....

#2

X=4; Y=2

а)y=16/4=4 -не подходит
б)y=1/16-не подходит
в)y=8/4=2 - Подходит
г)y=-8/4=-2 - не подходит
Ответ: В).
.....

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