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gunner51
@gunner51
July 2022
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решите 1 ое пожалуйста очень надо
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2-(3x-1)/4 >(4x+3)²-16x²+7x ⇔8-(3x-1)>4·[(4x+3)²-16x²]+4·7x⇔
⇔9-3x>4[(4x+3-4x)(4x+3+4x)]+28x ⇔9-3x>4·(3)·(8x+3)+28x ⇔
9-3x>96x+36 +28x⇔ -27>127x⇔x<-127/27
x<-127/27
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gunner51
ТУТ КАК БЫ -27\127
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Verified answer
2-(3x-1)/4 >(4x+3)²-16x²+7x ⇔8-(3x-1)>4·[(4x+3)²-16x²]+4·7x⇔⇔9-3x>4[(4x+3-4x)(4x+3+4x)]+28x ⇔9-3x>4·(3)·(8x+3)+28x ⇔
9-3x>96x+36 +28x⇔ -27>127x⇔x<-127/27
x<-127/27