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Jack001
@Jack001
July 2022
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Решите 17 задание. Срочно
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SashaB11
Verified answer
Дано:
m(CH₃CHO)p-p = 130г
w(CH₃CHO) = 50% = 0,50
+[Ag(HN₃)₂]OH
φпр. = 80% = 0,80
Найти:
m(CH₃COOH)пр.
Решение:
m(CH₃CHO) = m(CH₃CHO)p-p × w(CH₃CHO) = 130 × 0,50 = 65г
CH₃CHO + 2[Ag(HN₃)₂]OH → CH₃COOH + 2Ag + 4NH₃ + H₂O
Mr(CH₃CHO) = 44 г/моль
Mr(CH₃COOH) = 60 г/моль
m(CH₃COOH)теор. = (65×60)÷44 = 88,63г
m(CH₃COOH)пр. = m(CH₃COOH)теор. × φпр. = 88,63 × 0,80 = 70,9г
Ответ: m(CH₃COOH)пр. = 70,9г
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Answers & Comments
Verified answer
Дано:m(CH₃CHO)p-p = 130г
w(CH₃CHO) = 50% = 0,50
+[Ag(HN₃)₂]OH
φпр. = 80% = 0,80
Найти:
m(CH₃COOH)пр.
Решение:
m(CH₃CHO) = m(CH₃CHO)p-p × w(CH₃CHO) = 130 × 0,50 = 65г
CH₃CHO + 2[Ag(HN₃)₂]OH → CH₃COOH + 2Ag + 4NH₃ + H₂O
Mr(CH₃CHO) = 44 г/моль
Mr(CH₃COOH) = 60 г/моль
m(CH₃COOH)теор. = (65×60)÷44 = 88,63г
m(CH₃COOH)пр. = m(CH₃COOH)теор. × φпр. = 88,63 × 0,80 = 70,9г
Ответ: m(CH₃COOH)пр. = 70,9г