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gunay13
@gunay13
August 2022
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Решите 178 номер (2,4)
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Yrok0793
2)x(4x+1)=3(3x-1)
4x^2+x=9x-3
4x^2-8x+3=0
D=64-48=16
x1=4\8=0,5
x2=12\8=1,5
4) (x+1)(4x+1)=(x-3)(3x-8)
4x^2+x+4x+1=3x^2-8x-9x+24
x^2+22x-23
D=484+92=576
x1=-46\2=-23
x2=2\2=1
2 votes
Thanks 1
gunay13
Спасибо огромное ))
Yrok0793
Не за что)
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Answers & Comments
4x^2+x=9x-3
4x^2-8x+3=0
D=64-48=16
x1=4\8=0,5
x2=12\8=1,5
4) (x+1)(4x+1)=(x-3)(3x-8)
4x^2+x+4x+1=3x^2-8x-9x+24
x^2+22x-23
D=484+92=576
x1=-46\2=-23
x2=2\2=1