Решите 2 номера даю 50 БАЛЛОВ !!!Срочео ребят номера на фото .Нужно решение.Только номер 3 и 4!. Created by egornomer1. algebra-ru

Решите 2 номера даю 50 БАЛЛОВ !!!Срочео ребят номера на фото .Нужно решение.Толь...

Ilyasssssss $1)\frac{\sqrt{10}+5}{2+\sqrt{10}} = \frac{\sqrt{2\cdot 5}+5}{2+\sqrt{2\cdot 5}} =\frac{\sqrt5(\sqrt2+\sqrt5)}{\sqrt2(\sqrt2+\sqrt5)}=\frac{\sqrt5}{\sqrt2}=\sqrt{\frac{5}{2}}=\sqrt{2,5}\\\\\\2)\frac{x-3\sqrt{x}}{2\sqrt{x}-6}= \frac{\sqrt{x}(\sqrt{x}-3)}{2(\sqrt{x}-3)} =\frac{\sqrt{x}}{2}\\\\\\3) \frac{7}{2\sqrt{21}} = \frac{7}{2\sqrt{3\cdot 7}} =\frac{\sqrt7}{2\sqrt3}=\frac{\sqrt7\cdot \sqrt3}{2\cdot \sqrt3\cdot \sqrt3}= \frac{\sqrt{21}}{6}$

$4)\; \frac{22}{\sqrt{13}-\sqrt2} = \frac{22(\sqrt{13}+\sqrt2)}{(\sqrt{13}-\sqrt2)(\sqrt{13}+\sqrt2)} = \frac{22(\sqrt{13}+\sqrt2)}{13-2} = \frac{22(\sqrt{13}+\sqrt2)}{11} =\\\\=2(\sqrt{13}+\sqrt2)$

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3
a) (√10+5)(/2+√10)=√5(√2+√5)/√2(√2+√5)=√5/√2=√2.5
b) (x-3√x)/(2√x-6)=√x(√x-3)/2(√x-3)=√x/2
4
a) 7/2√21=7√21/42=√21/6
b) 22/(√13-√2)=22(√13+√2)/(√13-√2)(√13+√2)=22(√13+√2)/11=2(√13+√2)

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