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workinglogorifm
@workinglogorifm
August 2022
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решите 2 пример пожалуйста
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Бахит
ОДЗ,
x²-8x+12>0
x1-2=((8+-√64-48))/2=(8+-4)/2={2;6}
x∈(-∞;2)U(6;+∞)
x²-8x+12≤21, x²-8x-9≤0
x1-2=(8+-√(64+36))/2=(8+-10)/2={-1;9}, x∈[-1;9]
с учетом ОДЗ
x∈[-1;2)U(6;9]
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Answers & Comments
x²-8x+12>0
x1-2=((8+-√64-48))/2=(8+-4)/2={2;6}
x∈(-∞;2)U(6;+∞)
x²-8x+12≤21, x²-8x-9≤0
x1-2=(8+-√(64+36))/2=(8+-10)/2={-1;9}, x∈[-1;9]
с учетом ОДЗ
x∈[-1;2)U(6;9]