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dianadalla
@dianadalla
June 2022
1
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Решите 3,4,5,6 , пожалуйста , очень надо срочно ;(
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m11m
Verified answer
3.
(x-5)(x+3)(x+2)>0
x=5 x= -3 x= -2
- + - +
---------- -3
------------
-2 ------------- 5
-------------
\\\\\\\\\\\\\\\ \\\\\\\\\\\\\\
x∈(-3; -2)U(5; +∞)
4.
ОДЗ: x≠5
(x+2)(x-5)≤0
x= -2 x=5
+ - +
---------
-2 -----------
5 ----------------
\\\\\\\\\\\\\\
x∈[-2; 5)
5.
ОДЗ: x≠5
(2x-3)(x+7)(x-5)≥0
2(x-1.5)(x+7)(x-5)≥0
(x-1.5)(x+7)(x-5)≥0
x=1.5 x= -7 x=5
- + - +
---------
-7 ---------- 1.5
----------- 5 -
-----------
\\\\\\\\\\\ \\\\\\\\\\\\
x∈[-7; 1.5]U(5; +∞)
6.
ОДЗ: x≠ -5, x≠5
Разложим на множители:
x²-2x-35=(x+5)(x-7)
x²-2x-35=0
D=(-2)²-4*(-35)=4+140=144=12²
x₁=(2-12)/2= -10/2= -5
x₂=(2+12)/2=14/2=7
Сокращаем:
[(x+5)(x-7)]/[(x-5)(x+5)]≥0
(x-7)/(x-5) ≥ 0
(x-7)(x-5)≥0
x=7 x=5
+ - +
----------
5 -----------
7 -----------
\\\\\\\\\\\ \\\\\\\\\\
x∈(-∞; 5)U[7; +∞)
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Answers & Comments
Verified answer
3.(x-5)(x+3)(x+2)>0
x=5 x= -3 x= -2
- + - +
---------- -3 ------------ -2 ------------- 5 -------------
\\\\\\\\\\\\\\\ \\\\\\\\\\\\\\
x∈(-3; -2)U(5; +∞)
4.
ОДЗ: x≠5
(x+2)(x-5)≤0
x= -2 x=5
+ - +
--------- -2 ----------- 5 ----------------
\\\\\\\\\\\\\\
x∈[-2; 5)
5.
ОДЗ: x≠5
(2x-3)(x+7)(x-5)≥0
2(x-1.5)(x+7)(x-5)≥0
(x-1.5)(x+7)(x-5)≥0
x=1.5 x= -7 x=5
- + - +
--------- -7 ---------- 1.5 ----------- 5 ------------
\\\\\\\\\\\ \\\\\\\\\\\\
x∈[-7; 1.5]U(5; +∞)
6.
ОДЗ: x≠ -5, x≠5
Разложим на множители:
x²-2x-35=(x+5)(x-7)
x²-2x-35=0
D=(-2)²-4*(-35)=4+140=144=12²
x₁=(2-12)/2= -10/2= -5
x₂=(2+12)/2=14/2=7
Сокращаем:
[(x+5)(x-7)]/[(x-5)(x+5)]≥0
(x-7)/(x-5) ≥ 0
(x-7)(x-5)≥0
x=7 x=5
+ - +
---------- 5 ----------- 7 -----------
\\\\\\\\\\\ \\\\\\\\\\
x∈(-∞; 5)U[7; +∞)