Решите 4 и 5 СУПЕР СРОЧНО!!!. Created by leontievasv. algebra-ru

x - 4 = 36 - 12x + x²x² - 13x + 40 = 0D = (-13)² - 4 * 40 = 169 - 160 = 9Проверка: 2 = - 2 - неверно1 = 1 - верноОтвет: 55) 1) 2)

Решите 4 и 5 СУПЕР СРОЧНО!!!...

leontievasv @leontievasv

August 2021 1 1 Report

Решите 4 и 5 СУПЕР СРОЧНО!!!

Answers & Comments

Universalka

Verified answer

$( \sqrt{x-4}) ^{2} =(6 -x) ^{2}$
x - 4 = 36 - 12x + x²
x² - 13x + 40 = 0
D = (-13)² - 4 * 40 = 169 - 160 = 9
$X _{1} = \frac{13+ \sqrt{9} }{2}= \frac{13+3}{2}= 8$
$X _{2} = \frac{13- \sqrt{9} }{2}= \frac{13-3}{2} = 5$
Проверка: $\sqrt{8-4}= 6-8$
2 = - 2 - неверно
$\sqrt{5-4} =6-5$
1 = 1 - верно
Ответ: 5
5)
1) $\frac{3}{1- \sqrt{6} } - \frac{ \sqrt{6} }{ \sqrt{6+1} } = \frac{3 \sqrt{6}+3- \sqrt{6}+6 }{1 ^{2} -( \sqrt{6} ) ^{2} }= \frac{2 \sqrt{6}+9 }{1-6} =- \frac{2 \sqrt{6}+9 }{5}$
2) $- \frac{2 \sqrt{6} +9}{5} *(9- 2 \sqrt{6})=- \frac{(9+2 \sqrt{6)}(9-2 \sqrt{6}) }{5}=- \frac{9 ^{2} -(2 \sqrt{6}) ^{2} }{5} =- \frac{81-24}{5} = - \frac{57}{5}$ $= -11,4$

2 votes Thanks 2

reshite itogovyj srez po algebre i geometrii za klass

Answer

leontievasv October 2021 | 0 Ответы

srochno reshite 4 i 5 nomera

Answer

Answers & Comments

Verified answer

reshite itogovyj srez po algebre i geometrii za klass

srochno reshite 4 i 5 nomera

рекомендуемые вопросы

Helpful Links

Helpful Social