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den1998dovgan
@den1998dovgan
July 2022
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решите 8 интеграл, пожалуйста...
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au456
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Инт(0;1) (6x^2+3)dx= 6/3*(x^3)+3x (0;1)= 5-0=5
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Verified answer
Инт(0;1) (6x^2+3)dx= 6/3*(x^3)+3x (0;1)= 5-0=5