решите 984(бвге) спасибо. Created by BenDer2014. algebra-ru

решите 984(бвге) спасибо...

BenDer2014 @BenDer2014

August 2022 1 3 Report

решите 984(бвге)
спасибо

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NNNLLL54

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$1)\; \; 2\cdot 2\frac{2}{5}-2\frac{1}{2}\cdot 4+\frac{13}{15}=2\cdot \frac{12}{5}-\frac{5}{2}\cdot 4+\frac{13}{15}=\\\\= \frac{24}{5}-10+\frac{13}{15}=\frac{72-50+13}{15}= \frac{35}{15}= \frac{7}{3}=2\frac{1}{3}\\\\2)\; \; 15\frac{6}{7}-12\frac{6}{7}\cdot (\frac{1}{10}+\frac{1}{15})= \frac{111}{7}-\frac{90}{7}\cdot \frac{3+2}{30}= \frac{111}{7}-\frac{90}{7}\cdot \frac{5}{30}=\\\\= \frac{111}{7}-\frac{3\cdot 5}{7}= \frac{96}{7}=13\frac{5}{7}$

$3)\; \; (3\frac{1}{5}-3\frac{7}{10}):1\frac{1}{4}+2\frac{3}{4}=(\frac{16}{5}-\frac{37}{10}): \frac{5}{4}+\frac{11}{4}=\\\\=\frac{32-37}{10}\cdot \frac{4}{5}+ \frac{1}{4}=-\frac{5}{10}\cdot \frac{4}{5}+\frac{1}{4}=-\frac{2}{5}+ \frac{1}{4}=\frac{-8+5}{20} =- \frac{3}{20}\\\\4)\; \; (2,125\cdot 1\frac{15}{17} -1\frac{7}{12}):7,25=(2\frac{1}{8}\cdot \frac{32}{17}-\frac{19}{12}):7\frac{1}{4}=$

$=(\frac{17}{8}\cdot \frac{32}{17}-\frac{19}{12}):\frac{29}{4}=(4-\frac{19}{12})\cdot \frac{4}{29}= \frac{29}{12}\cdot \frac{4}{29}=\frac{1}{3}$

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