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Панда12377
@Панда12377
July 2022
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Решите А1.а,б,в.
Помогите,пожалуйста!:(
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Nik231506
А) x^2-6=x
x^2-x=6
x=6
б) 20=x(9-x)
9x-x^2=20
x^2-9x+20=0
D=(-9)^2-4*1*20=81-80=1
x1=9+1/2=5
x2=9-1/2=4
в) (x-4)(x+4)=x(2x+10)
x^2+4x-4x-16=2x^2+10x
-x^2-16-10x=0
x^2+10x+16=0
D=10^2-4*1*16=100-64=36
x1=(-10)+6/2=-2
x2=(-10)-6/2=-8
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Answers & Comments
x^2-x=6
x=6
б) 20=x(9-x)
9x-x^2=20
x^2-9x+20=0
D=(-9)^2-4*1*20=81-80=1
x1=9+1/2=5
x2=9-1/2=4
в) (x-4)(x+4)=x(2x+10)
x^2+4x-4x-16=2x^2+10x
-x^2-16-10x=0
x^2+10x+16=0
D=10^2-4*1*16=100-64=36
x1=(-10)+6/2=-2
x2=(-10)-6/2=-8