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kristi121202
@kristi121202
June 2022
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РЕШИТЕ B5 ПОЖАЛУЙСТА
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rubilovalex
X=3-y
(3-y)y=1
3y-y²=1 ⇒ y²-3y+1=0
D=5
y1=
y2=
x1=
x2=
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kristi121202
А откуда вы взяли эти значения?
kristi121202
Все понятно
fadarm
Verified answer
X^2-xy+y^2=x^2+2xy+y^2-2xy-xy=(x+y)^2-3xy. подставляем значения: 3^2--3*1=9-3=6. я думаю так.
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Answers & Comments
(3-y)y=1
3y-y²=1 ⇒ y²-3y+1=0
D=5
y1=
y2=
x1=
x2=
Verified answer
X^2-xy+y^2=x^2+2xy+y^2-2xy-xy=(x+y)^2-3xy. подставляем значения: 3^2--3*1=9-3=6. я думаю так.