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ewsdasd
@ewsdasd
June 2022
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Решите биквадратное уравнение:
(х^2-4)^2+3(x^2-4)-10=0
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Answers & Comments
SarvarJURAEV
(х^2-4)=t
t^2+3t-10=0
D=49
t1=-5, t2=2
x^2-4=-5
x^2=-1
x1=1
x^2-4=2
x^2=6
x2=
√6
1 votes
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Answers & Comments
t^2+3t-10=0
D=49
t1=-5, t2=2
x^2-4=-5
x^2=-1
x1=1
x^2-4=2
x^2=6
x2=√6