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Нооатак
@Нооатак
July 2022
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решите биквадратное уравнение x^4 - 5х^2 + 4 = 0
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Trp
Ответ: x1=2; x2=-2; x3=1; x4=-1
1 votes
Thanks 1
AnonimusPro
Verified answer
Замена x^2=t; t>0
t^2-5t+4=0
(t-4)(t-1)=0
t1=4
t2=1
Обратная замена:
1)х^2=4. 2)х^2=1
х1,2=(-4;4). x3,4=(-1;1)
2 votes
Thanks 0
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Answers & Comments
Ответ: x1=2; x2=-2; x3=1; x4=-1
Verified answer
Замена x^2=t; t>0t^2-5t+4=0
(t-4)(t-1)=0
t1=4
t2=1
Обратная замена:
1)х^2=4. 2)х^2=1
х1,2=(-4;4). x3,4=(-1;1)