Решите цепочку превращения (структурная нужна):
CH3COONa-CH4-CH3Cl-C2H6-C2H5-Cl-C2H6-CO2
1) CH3COONa + NaOH = CH4 + Na2CO3
2) CH4 + Cl2 = CH3Cl + HCl
3) 2CH3Cl + 2Na = C2H6 + 2NaCl
4) C2H6 + Cl2 = C2H5Cl + HCl
5) - ?
6) 2C22H6 + 7O2 = 4CO2 + 6H2O
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Verified answer
1) CH3COONa + NaOH = CH4 + Na2CO3
2) CH4 + Cl2 = CH3Cl + HCl
3) 2CH3Cl + 2Na = C2H6 + 2NaCl
4) C2H6 + Cl2 = C2H5Cl + HCl
5) - ?
6) 2C22H6 + 7O2 = 4CO2 + 6H2O