D=(4)^2-4*1*3=16-12=4
x1=-4+2/2=-1
x2=-4-2/2=-3
x^2 + 4х + 3 = 0
D = k^2 - ac
k = 1/2b
D = 2^2 - 3 × 1 = 4 - 3 = 1
x = (- 2 ± √1)/1 = (-2 ± 1) = - 3; -1
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
D=(4)^2-4*1*3=16-12=4
x1=-4+2/2=-1
x2=-4-2/2=-3
x^2 + 4х + 3 = 0
D = k^2 - ac
k = 1/2b
D = 2^2 - 3 × 1 = 4 - 3 = 1
x = (- 2 ± √1)/1 = (-2 ± 1) = - 3; -1