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polldap08
@polldap08
July 2022
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решите что сможете пожалуйста,очень надо)
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EnotPraga
Надеюсь понятно. Последнее не решила.
1)
a) (а+4)/(4a)*(8a^3)/(a^2-16)=(a+4)/(4a)*(8a^3)/((a+4)(a-4))=(2a^2)/(a-4)
б) ((3x^2y^-3)/(z))^2)/((3x)^3z^-2)/(y^5)=(9x^4y^-6)/(z^2)*((y^5)/(27x^3)=(9x^4y^-11)/(27x^3)=(xy^-11)/3=x/(3y^-11)
2)
=(5^4*0.2^-2)/5^6=5^2/5^2=1
3)
=x+(81/x)=18
x^2+81=18x
x^2-18x+81=0
D=0
x=9
4)
=(b+1)/(b-1)-(b)/(b+1)=((b+1)^2-b(b-1))/((b-1)(b+1))=(b^2+2b+1-b^2+b)/((b-1) (b+1))=(3b+1)/((b-1) (b+1))
=(3b+1)/((b-1) (b+1))*(2(b-1))/(3b+1)=2/(b+1)
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Answers & Comments
1)
a) (а+4)/(4a)*(8a^3)/(a^2-16)=(a+4)/(4a)*(8a^3)/((a+4)(a-4))=(2a^2)/(a-4)
б) ((3x^2y^-3)/(z))^2)/((3x)^3z^-2)/(y^5)=(9x^4y^-6)/(z^2)*((y^5)/(27x^3)=(9x^4y^-11)/(27x^3)=(xy^-11)/3=x/(3y^-11)
2)
=(5^4*0.2^-2)/5^6=5^2/5^2=1
3)
=x+(81/x)=18
x^2+81=18x
x^2-18x+81=0
D=0
x=9
4)
=(b+1)/(b-1)-(b)/(b+1)=((b+1)^2-b(b-1))/((b-1)(b+1))=(b^2+2b+1-b^2+b)/((b-1) (b+1))=(3b+1)/((b-1) (b+1))
=(3b+1)/((b-1) (b+1))*(2(b-1))/(3b+1)=2/(b+1)