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nastusha2014879
@nastusha2014879
August 2022
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решите:
cos2x+1=0
2sin2x-корень2=0
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amin07am
Verified answer
Ответ ответ ответ ответ ответ ответ
1 votes
Thanks 2
nastusha2014879
cos2x+1=0 тут ответ:п/2+Пп,ПэZ
sedinalana
Verified answer
1
сos2x=-1
2x=π+2πn
x=π/2+πn,n∈z
2
2sin2x=√2
sin2x=√2/2
2x=(-1)^n*π/4+πn
x=(-1)^n*π/8+πn/2,n∈z
0 votes
Thanks 1
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Verified answer
Ответ ответ ответ ответ ответ ответVerified answer
1сos2x=-1
2x=π+2πn
x=π/2+πn,n∈z
2
2sin2x=√2
sin2x=√2/2
2x=(-1)^n*π/4+πn
x=(-1)^n*π/8+πn/2,n∈z