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Валентина09
@Валентина09
July 2022
1
18
Report
Решите ^-cтепень а)
(
b^2
+1
)
(
3b
−
b^3
)
−
(
3b
−
b^5
)
=
б)(
2x
−
3y
)
(
3x
+
2y
)
−
(
6
x^2
−
5x
y
)=
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Answers & Comments
neogan99
A) (b
^2+1)(3b-b
^3)-(3b-b
^5)
(3b
^3-b
^5+3b-b
^3
)-(3b-b
^5)
-b
^5+3b-3b+b
^5
Ответ: 0
b) (2x-3y)(3x+2y)-(6x
^2-5xy)
(6x
^2+4xy-6xy-6y
^2)-(6x
^2-5xy)
6x
^2-2xy-6y
^2-6x
^2+5xy
3xy-6y
^2
3y(x-2y)
Ответ; 3y(x-2y)
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Answers & Comments
(3b^3-b^5+3b-b^3)-(3b-b^5)
-b^5+3b-3b+b^5
Ответ: 0
b) (2x-3y)(3x+2y)-(6x^2-5xy)
(6x^2+4xy-6xy-6y^2)-(6x^2-5xy)
6x^2-2xy-6y^2-6x^2+5xy
3xy-6y^2
3y(x-2y)
Ответ; 3y(x-2y)