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Dimonikom
@Dimonikom
July 2022
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Universalka
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Заменим частное произведением и решим методом интервалов
(x² - 1)(x² - 2x) > 0
(x + 1)(x - 1)x(x - 2) > 0
+ - + - +
__________₀__________₀____________₀____________₀____________
- 1 0 1 2
x ∈ (- ∞ ; - 1)∪[0 , 1)∪(2 ; + ∞)
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Answers & Comments
Verified answer
Заменим частное произведением и решим методом интервалов
(x² - 1)(x² - 2x) > 0
(x + 1)(x - 1)x(x - 2) > 0
+ - + - +
__________₀__________₀____________₀____________₀____________
- 1 0 1 2
x ∈ (- ∞ ; - 1)∪[0 , 1)∪(2 ; + ∞)