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yultaeva88
@yultaeva88
July 2022
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Решите дифференциальное уравнение...yy'=-3x
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flsh
Y·y' = - 3x
ydy = -3xdx
y²/2 = -3x²/2 + C₁
y² = -3x² + C
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Answers & Comments
ydy = -3xdx
y²/2 = -3x²/2 + C₁
y² = -3x² + C