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NewMzplotnik
@NewMzplotnik
July 2022
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Решите два уравнения:
1) (Х+4)² > 2а² - 48 - 4а
2) 2х² + 7х + 3 ≤ 0
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PavelAleksei1999g
(a+b)^2 (квадрат суммы) = a^2+2ab+b^2x^2+2*x*4+4^2>2a(a-2)-482) D=b2-4acD=7^2-4*2*3=...x1,x2(-b+-sqrt(D))/2a...
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NewMzplotnik
Мне бы полное решение
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